Question

given the perimeter of a triangle is 240 m. if two of its sides are 50 m and 78 m, find the length of perpendicular on the smallest side from the opposite vertex.

Answer 1

perimeter = 240 m
the given sides r 50m n 78 m in length
so the 3rd side is = 240-50-78=112 m
therefore the smallest side is 50 m.
now area of the triangle is √s(s-a)(s-b)(s-c) [ where s = 1/2(a+b+c) = 120]
Area = √ 120*70*8*42 = 1680
we know that a = 1/2* b* h
so h= 2a/b = 2*1680/50 = 67.2 m