Question

Given the point (1, -2). Find the equation of four lines which passes through the given
point​

Answer 1

Answer:

y+6=−(x−1)

y=−x−7

Explanation:

Use point/slope form:

y−y1=m(x−x1)

y+6=−(x−1)

This is an acceptable form of a linear equation by most teachers, but some prefer simplifying down to slope/intercept form:

Subtract 6 to each side:

y=−(x+1)−6

Distribute the negative to the parentheses:

y=−x−1−6

Simplify:

y=−x−7

Answer 2

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Ans is x + 4 = 0

Explanation :-

The equation of a line parallel to y axis is

x = k where k is constant. …..(1)

It is given that the line parallel to y axis passes through the point (-4,-5).

Therefore (-4,-5) will satisfy equation (1)

Hence , -4 = k

Equation (1) becomes

x = -4

=> x + 4 = 0

Hope it helps.