Question

Given the point (-3,5) find a equation of line on which it lie.​

Answer 1

7x−3y−36=0

A general equation for line having slope m is , y = mx + c , where m is slope of line .

Here m =

3

7

,

So, 3y=7x+3c or 3y=7x+C

Now to eliminate C we will use the information that line passes through (3,-5),

−15=7(3)+C which gives c=−36 .

So equation of line is , 7x−3y−36=0 .

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