given the points A (-1,2) and B(2,k) find the values (s) of k such that the length (AB) is 5 units
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Hey there,
A≡(-1,2)
B≡(2,k)
AB= 5 units
AB=√{2-(-1)}²+(k-2)²
Squaring both sides, we get-
25=9+(k-2)²
(k-2)²=16
k-2=4
k=6
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
071610220
Ace
A≡(-1,2)
B≡(2,k)
AB= 5 units
AB=√{2-(-1)}²+(k-2)²
Squaring both sides, we get-
25=9+(k-2)²
(k-2)²=16
k-2=4
k=6
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
071610220
Ace
07161020:
plz mark as brailiest
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