Question

given the points A minus one, two and B two,k find the values of K such that the length ab is 5 units

Answer 1

Hey there,

A≡(-1,2)
B≡(2,k)
AB= 5 units

AB=√{2-(-1)}²+(k-2)²
Squaring both sides, we get-

25=9+(k-2)²
(k-2)²=16
k-2=4
k=6

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