Question

Given the polynomial function below, find f(-1). F(x)=-x3-x2+1

Answer 1

Question:

From the given the polynomial function

f(x) = -x^3 - x^2 + 1 , find f(-1) .

Answer:

f(-1) = 1

Solution:

If f(x) is given , then to find the value of f(a) , we just need to put x = a , everywhere in the expression of f(x).

Here,

f(x) = -x^3 - x^2 + 1

Thus,

=> f(-1) = -(-1)^3 - (-1)^2 + 1

=> f(-1) = -(-1) - 1 + 1

=> f(-1) = 1-1+1

=> f(-1) = 1

Hence,

The required value of f(-1) is 1 .

Answer 2

Your question contains some missing words. So, I write your question correctly.

Question:

Given the polynomial function below, find f(-1) where the polynomial f(x)= -x³ - x² + 1 is given.

Answer:

f(-1) = 1

Step-by-step explanation:

Let us assume that f(x) is given, to find the value of f(a), we have to just need to put x = a, in the expression of polynomial f(x)

Given,

f(x) = x³ - x² + 1

So,

=> f(-1) = -(-1)³ -(-1)² + 1

=> f(-1) = -(-1) - 1 + 1

=> f(-1) = 1

.°. f(-1) = 1

Therefore, the required value of f(-1) in the given polynomial is 1.