Question

given the R.I is 4/3 if real depth of the particle 64 cm, the apparent depth is?

a)12cm
b)24cm
c)36cm
d)48cm​

Answer 1

Answer:

refractive index =real depth /apparent depth

refactive index x  apparent depth=real deth

apparent depth=real depth/refractive index

apparent depth =4/3 /64

apparent depth=64 x 4 /3

apparent depth =85.33cm

Answer 2

Answer:

The correct answer is equal to option (d).

Explanation:  

The refractive index of the any is equal to the ratio of real depth to apparent depth.

u denoted as the refractive index of any medium.

H denoted as the real depth.

$H^{'}$ denoted as the apparent depth.

$u=\frac{H}{H^{'} }$

$\frac{4}{3} =\frac{64}{H^{'} }$

$H^{'} =48cm$

So, the apparent depth of the particle is equal to 48cm.