given the refractive index of benzene equal to 1.50 and the speed of light in air is equal to 3 into 10 raise to 8 metre per second calculate the percent of reduction of speed off light when it travels from air to benzene
Answers
Answered by
4
HEY MATE HERE'S YOUR ANSWER!
Refractive Index = Speed of light in Air / Speed of light in medium
Speed of light in medium = Speed of light in air / Refractive index
=> Speed of light in medium = 3 × 10⁸ / 1.5
=> Speed of light in medium = 2 × 10⁸ m/s
So, Percentage Change = ( Change in Speed / Speed of light in air ) * 100
=> Change in Speed = 3 × 10⁸ - 2 × 10⁸
=> Change in speed = 10⁸ ( 3 - 2 ) = 10⁸
=> Percentage change = ( 10⁸ / 3 × 10⁸ ) * 100
=> Percentage change = ( 1 / 3 ) * 100
=> Percentage change =33.34%
Refractive Index = Speed of light in Air / Speed of light in medium
Speed of light in medium = Speed of light in air / Refractive index
=> Speed of light in medium = 3 × 10⁸ / 1.5
=> Speed of light in medium = 2 × 10⁸ m/s
So, Percentage Change = ( Change in Speed / Speed of light in air ) * 100
=> Change in Speed = 3 × 10⁸ - 2 × 10⁸
=> Change in speed = 10⁸ ( 3 - 2 ) = 10⁸
=> Percentage change = ( 10⁸ / 3 × 10⁸ ) * 100
=> Percentage change = ( 1 / 3 ) * 100
=> Percentage change =33.34%
Mrstyles:
hw r u
Fine
Fine and u
ok
studying
Mmmm
r u?
oh ok
hw is things going
Good
Answered by
2
hope it helps u
pls... mark as brainliest becoz its correct and igave answer first
Attachments:
sry i didnt see that girl alredy answered so i edit my txt that i didnt answer first
Similar questions