Question

Given the sequence 3,1,-1,-3..... find the 12th term

Answer 1

Answer:

Step-by-step explanation:

IT IS AN AP

where a, first term= 3

common difference = 1-3

                                  =-2

a₁₂ = a+19 d

     = 3+19(-2)

     =3-38

     = -35

thus , -35 is 12th  term

HOPE IT HELPS........

Answer 2

$\mathfrak{Answer:-}$

Here,

first term(a) = 3

Common difference(d) = 1 - 3 = -2

No. of terms(n) = 12

As we know

$\boxed{an\:=\:a+(n-1)d}$

Substituting the values we get,

a12 = 3+(12-1)(-2)

a12 = 3+(-22)

a12 = -19

Hence, the 12th term is -19