Given the simultaneous equations,
x= -2y+15
x=y²
the solutions are :
Answers
Answered by
2
OMG you are asking so many questions so quickly
After a bit of substitution we can get y² + 2y - 15 = 0
I think you can solve this equation without any worries (✿◠‿◠)
Answered by
0
Answer:
y^2+2y-15=0
y^2+5y-3y-15=0
y(y+5)-3(y+5)=0
(y-3)(y+5)=0
(3,-5)
hope it helps.
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