Math, asked by Anonymous, 3 months ago

Given the simultaneous equations,

x= -2y+15
x=y²
the solutions are :

Answers

Answered by adhirajsinghbrar2005
2

OMG you are asking so many questions so quickly

After a bit of substitution we can get y² + 2y - 15 = 0

I think you can solve this equation without any worries (✿◠‿◠)

Answered by umairkhan009
0

Answer:

y^2+2y-15=0

y^2+5y-3y-15=0

y(y+5)-3(y+5)=0

(y-3)(y+5)=0

(3,-5)

hope it helps.

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