Question

Given, the square of the hypotenuse of an isosceles right-angled triangle is equal to 2 m the other two sides are??

Answer 1

Answer:

The other two sides are of √2 m each.

Step-by-step explanation:

In ΔABC

AB² + BC² = AC²                                                 [∵Pythagoras Theorem]

Now, as the triangle is isosceles

⇒ AB = BC

⇒ AB² + AB² = AC²

Now it is given that the hypotenuse = 2m

⇒ 2AB² = [2]²

⇒ AB² = 4÷2

⇒ AB = √2

∴ The other two sides are of √2 m each.