Question

Given the two concentration of hcn are 0.1m and 0.001m respectively,find the degree of dissociation

Answer 1

Given, the two concentration of HCN are 0.1M and 0.001M respectively.

we have to find degrees of dissociation of HCN.

Let $\alpha$ is degree of dissociation of HCN.

dissociation reaction is ....

$HCN+H_2O\Leftrightarrow H_3O^++CN^-$

initial concentration of HCN = 0.1M

at equilibrium,

concentration of HCN = 0.01M =$0.1(1-\alpha)$

or, $0.01=0.1(1 -\alpha)$

or, 0.9 = $\alpha$

hence degree of dissociation of HCN is 0.9 or 90%.