Question

Given the values of x ,y and z, evaluate the following (Answer in true / false):


(x>=y) || (! (z==y) && (z<x))


a) x=10, y=5, z=11

b) x=9, y=10, z=2

and plz tell how you solved it.​

Answer 1

Answer:

a) true

b)false

please follow

Answer 2

Solution To Question 1:

Given:

• x = 10
• y = 5
• z = 10

So,

(x>=y) || (!(z==y) && (z<x))

= (10>=5) || (!(10==5) && (10 < 10))

= True || (!False && False)

= True || (True && False)

= True || False

= True (See the Truth Table)

Solution To Question 2:

Given:

• x = 9
• y = 10
• z = 2

So,

(x>=y) || (!(z==y) && (z<x))

= (9>=10) || (!(2==10) && (2<10))

= False || (!True && True)

= False || (False && True)

= False || False

= False

Answer:

• True
• False

Truth Table:

$\boxed{\begin{array}{c|c|c|c}\tt op-1:&\tt op-2:&\tt op-1\:||\:op-2&\tt op-1\:\&\&\:op-2\\ \tt True&\tt True&\tt True&\tt True\\ \tt True&\tt False&\tt True&\tt False\\ \tt False&\tt True&\tt True&\tt False\\ \tt False&\tt False&\tt False&\tt False\end{array}}$

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