Math, asked by harshu494, 1 year ago

given things are given plz help to find the ans

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harshu494: hi tq
gogoibanti55: hlo
gogoibanti55: I m simran

Answers

Answered by snehagupta24
1

Answer:


Step-by-step explanation:

i am using A instead of theta...

tanA + sinA = m

tanA - sinA=n

LHS = m^2-n^2

=(tan A+sinA)^2 - (tanA-sinA)^2

=(tanA+sinA+tanA-sinA)(tanA+sinA-tanA-sinA)

=2tanA*2sinA

=4 sinA/cosA* sinA

=4sin^2/cosA

RHS

4* root of mn

4 root of (tanA+sinA)(tanA-sinA)

=4 root of (tan^2 A-sin^2 A)

4 root of (sin^2A/cos^A2 - sin^2A)

=4 root of sin^A(1-cos^2A)/cos^2A

=4 root of sin^2A *sin^2A/cos^2A

=4sin^2A/cosA



harshu494: thank u so much
gogoibanti55: hii harsh
Answered by rupali8153gmailcom2
0
hope this answer is helpful plz mark it as brainliest
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