Question

given triangle ABC is congruent to triangle pqr of a b upon PQ is equal to 1 upon 3 then find area of triangle ABC upon a triangle pqr

Answer 1

GIVEN:
ΔABC ~ Δ PQR & AB/PQ = 1/3
ar(ΔABC)/ar( Δ PQR )= AB²/ PQ²
[The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]
ar(ΔABC)/ar( Δ PQR ) = 1²/3²
[Given =AB/PQ = ⅓]
ar(ΔABC)/ar( Δ PQR ) = 1/9

Hence, the Area of ΔABC/Area of ΔPQR = 1/9

HOPE THIS WILL HELP YOU….

Answer 2

Solution :-

Given that, Δ ABC ~ Δ PQR

and, 

AB/PQ = 1/3

We know that the ratio of two similar triangles is equal to the ratio of the squares of their corresponding sides.

So,

Area of Δ ABC/Area of Δ PQR = (AB)²/(PQ)²

⇒ (1)²/(3)²

⇒ 1/9

so, Area of triangle ABC/Area of triangle PQR is 1/9

Answer.