given triangle ABC is congruent Triangle pqr if ab/pq=1/3 then find area of triangle abc / pqr
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GIVEN:
ΔABC ~ Δ PQR & AB/PQ = 1/3
ar(ΔABC)/ar( Δ PQR )= AB²/ PQ²
[The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]
ar(ΔABC)/ar( Δ PQR ) = 1²/3²
[Given =AB/PQ = ⅓]
ar(ΔABC)/ar( Δ PQR ) = 1/9
Hence, the Area of ΔABC/Area of ΔPQR = 1/9
HOPE THIS WILL HELP YOU….
ΔABC ~ Δ PQR & AB/PQ = 1/3
ar(ΔABC)/ar( Δ PQR )= AB²/ PQ²
[The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.]
ar(ΔABC)/ar( Δ PQR ) = 1²/3²
[Given =AB/PQ = ⅓]
ar(ΔABC)/ar( Δ PQR ) = 1/9
Hence, the Area of ΔABC/Area of ΔPQR = 1/9
HOPE THIS WILL HELP YOU….
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