Question

given triangle ABC is similar to triangle pqr if a b upon PQ equal to 1 by 3 then find area of triangle ABC upon Triangle pqr

Answer 1

Hope it will help you

Answer 2

Answer:

$\frac{area\:\triangle ABC}{area\: \triangle PQR}=\frac{1}{9}$

Step-by-step explanation:

$Given \:\triangle ABC \:similar\:to\: \triangle PQR\\and\:\frac{AB}{PQ}=\frac{1}{3}$

$We\:know\:the\:theorem :\\The\:ratio\:of\:the\:areas\\of\:two\: similar\: triangles\\is\:equal\:to\:the\:ratio\:of\\the\: squares\:of\:their\\ corresponding\:sides.$

$Now,\:\frac{area\:\triangle ABC}{area\: \triangle PQR}=\frac{AB^{2}}{PQ^{2}}\\=\big(\frac{AB}{PQ}\big)^{2}\\=\big(\frac{1}{3}\big)^{2}$

/* From (1)*/

$=\frac{1}{9}$

Therefore,

$\frac{area\:\triangle ABC}{area\: \triangle PQR}=\frac{1}{9}$

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