Question

given triangle ABC is similar to triangle pqr if a b upon PQ equal to 1 by 3 then find area triangle ABC upon Triangle pqr

Answer 1

hope it will help you...

Answer 2

Given that both triangle are similar, we can apply the following formula:

$\dfrac{\text{Area 1}}{\text {Area 2}} = \bigg( \dfrac{\text{Length 1}}{\text{length 2}} \bigg)^2$

The ratio of the two length is 1 : 3 (Given)

Find the ratio of the area:

$\dfrac{\text{ABC}}{\text {PQR}} = \bigg( \dfrac{1}{3} \bigg)^2$

$\dfrac{\text{ABC}}{\text {PQR}} = \dfrac{1}{9}$

Answer: 1/9