Given triangle ABC similer triangle PQR, if AB upon PQ=1/3,then find area ABC/area PQR
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Answered by
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∵ Δ ABC ≈ Δ PQR
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( AB/PQ)²
( According to the theorem on similarity of triangles)
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( 1/3)²
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = 1 / 9
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( AB/PQ)²
( According to the theorem on similarity of triangles)
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = ( 1/3)²
∴ Ar ( Δ ABC ) / Ar ( Δ PQR ) = 1 / 9
Sakshu11:
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