Given triangle abc~triangle pqr ,if ab /pq =1/3 ,then find ar (triangle abc and area of triangle pqr
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Since ratio of square of corresponding sides of similar triangles is equal to the ratio of areas of two triangles , therefore
(1/3)×(1/3) = ( ar abc/ar pqr)
1/9 = ( ar abc/ar pqr)
(1/3)×(1/3) = ( ar abc/ar pqr)
1/9 = ( ar abc/ar pqr)
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