Question

given triangle ABC~TRIANGLE PQR,IF AB/PQ IS 1/3, THEN FIND area triangle ABC/ area triangle PQR

Answer 1

 
ar(ABC)/ar(PQR)=(AB/PQ)^2
=(1/3)^2
=1/9

Answer 2

Given :- ∆ABC ~ ∆ PQR

Since , The ratio of area of similar triangle is equal to the square of their corresponding side.

area of ∆ABC / area of ∆ PQR =
( AB / PQ )²

=> ( 1/3)²

=>

$\frac{1}{9}$

1:9