Given triangle GKH with KG = 15, HK = 13,GH = 14. Let KM = 12 be the altitude. If HM = 5, which is the largest acute angle?
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Given : KG = 15, HK = 13,GH = 14.
KM = 12 be the altitude.
HM = 5
To Find : which is the largest acute angle
Solution:
KG = 15, HK = 13,GH = 14.
13² + 14² > 15² hence its an acute angles triangle
Largest acute angle will be opposite side KG = 15 Hence angle H
HM = 4 , KM = 12 and HK = 13 is a right angles triangles
Hence Sin H = 12/13
=> H = Sin⁻¹(12/13) or Cos⁻¹(5/13) or Tan⁻¹(12/5)
=> H = 67.38°
and H is the largest angle
Largest acute angle is 67.38°
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