Question

Given triangle PQR with RS bisecting ZR. PQ extended to D and Zn is a right angle, then R m POP ano D S​

Answer 1

Answer:

In ∠PQR,

p+q+∠R=180°

⟹∠R=180°−(p−q)

RS is the bisector of ∠R.

So, ∠SRP=

2

1

{180°−(p+q)}

=90°−

2

1

(p+q)

given n=90°

From △RTO, m+∠SRT=90°

⟹∠m+90°−

2

1

(p+q)=90°

⟹∠m=

2

1

(∠p+∠q)

Step-by-step explanation:

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