Question

Given triangles ABC Similar triangles PQR ,if AB/PQ=1/3, then find ar triangles ABC /triangles PQR

Answer 1

The ratio of areas of triangle is 1:9
By theorem
The ratio of areas of triangles is equal to the ratio squares of sides of the the triangles

Answer 2

Answer:

$\frac{1}{9}$

Step-by-step explanation:

It is given that  triangle ABC is similar to triangle PQR, then the ratio of the area triangle ABC to the area of triangle PQR will be:

$\frac{area{\triangle}ABC}{area{\triangle}PQR}=\frac{(AB)^2}{(PQ)^2}$

Now, we are also given that $\frac{AB}{PQ}=\frac{1}{3}$

Therefore, $\frac{(AB)^2}{(PQ)^2}=\frac{1}{9}$

Thus, $\frac{area{\triangle}ABC}{area{\triangle}PQR}=\frac{1}{9}$.