Question

given two concentration HCN are .1M and .001M respectively what will be the ratio of degree of dissociation.​

Answer 1

Answer:

Given, the two concentration of HCN are 0.1M and 0.001M respectively.

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....HCN+H_2O\Leftrightarrow H_3O^++CN^-HCN+H2O⇔H3O++CN−

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....HCN+H_2O\Leftrightarrow H_3O^++CN^-HCN+H2O⇔H3O++CN−initial concentration of HCN = 0.1M

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....HCN+H_2O\Leftrightarrow H_3O^++CN^-HCN+H2O⇔H3O++CN−initial concentration of HCN = 0.1Mat equilibrium,

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....HCN+H_2O\Leftrightarrow H_3O^++CN^-HCN+H2O⇔H3O++CN−initial concentration of HCN = 0.1Mat equilibrium,concentration of HCN = 0.01M =0.1(1-\alpha)0.1(1−α)

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....HCN+H_2O\Leftrightarrow H_3O^++CN^-HCN+H2O⇔H3O++CN−initial concentration of HCN = 0.1Mat equilibrium,concentration of HCN = 0.01M =0.1(1-\alpha)0.1(1−α)or, 0.01=0.1(1 -\alpha)0.01=0.1(1−α)

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....HCN+H_2O\Leftrightarrow H_3O^++CN^-HCN+H2O⇔H3O++CN−initial concentration of HCN = 0.1Mat equilibrium,concentration of HCN = 0.01M =0.1(1-\alpha)0.1(1−α)or, 0.01=0.1(1 -\alpha)0.01=0.1(1−α)or, 0.9 = \alphaα

Given, the two concentration of HCN are 0.1M and 0.001M respectively.we have to find degrees of dissociation of HCN.Let \alphaα is degree of dissociation of HCN.dissociation reaction is ....HCN+H_2O\Leftrightarrow H_3O^++CN^-HCN+H2O⇔H3O++CN−initial concentration of HCN = 0.1Mat equilibrium,concentration of HCN = 0.01M =0.1(1-\alpha)0.1(1−α)or, 0.01=0.1(1 -\alpha)0.01=0.1(1−α)or, 0.9 = \alphaαhence degree of dissociation of HCN is 0.9 or 90%.

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