Question

given two concentric circles of radii 5 and 3 find that length of a chord of larger circle which touches the smaller one. if bd= 5 find bc​

Answer 1

Answer:

The measure of the BC is 0.7574 unit .

Step-by-step explanation:

Given as :

The radius of smaller circle = r = 3 unit

The radius of larger circle = R = 5 unit

The measure of BD = 5 unit

Let The measure of BC = x unit

According to question

From figure shown

∵ BD = 5 unit

BC = BD - CD          ........1

From smaller circle

Since, The chord of smaller circle and radius makes right angle at center O

So, OD² + OC² = CD²

I,e CD² = r² + r²

Or, CD² = 2 r²

or, CD² = 2 × 3²

or, CD² = 18

∴  CD = √18

I.e CD = 3√2 unit

From eq 1

∵  BC = BD - CD    

Or, BC = 5 unit -  3√2 unit

Or, BC = 0.7574 unit

So, The measure of the BC = 0.7574 unit

Hence, The measure of the BC is 0.7574 unit . Answer

Answer 2

Step-by-step explanation:

the length of chord of bigger circle is 8 units ;

the length of BC is 3.2 units