Question

Given two concentric circles of radii 5 and 3,find the lenth of a chord of larger circle which touches the smaller one.If BD=5 find BC​

Answer 1

Given two concentric circles of radii 5 and 3,find the lenth of a chord of larger circle which touches the smaller one.If BD=5 find BC

Answer:

∠OPA = ∠OPB =90°

Step-by-step explanation:

Let the two concentric circles be C₁and C₂  and the center O.

AB is the chord to the larger circle C₂ which touches the smaller circle C₁

Length of AB will be given by

Connecting OP , OA and Ob we get

OP = 3cm = radius of smaller circle.

OA = OB = 5cm = radius of larger circle.

∵ AB is tangent to circle C₁ OP ⊥ AB

∴∠OPA = ∠OPB =90°

For similar questions check ou

https://brainly.in/question/15897513?answeringSource=greatJob%2FquestionPage%2F1

https://brainly.in/question/15910430?answeringSource=greatJob%2FquestionPage%2F2

https://brainly.in/question/15935261?answeringSource=greatJob%2FquestionPage%2F3