Question

Given two double values d1. d2, why isn't it reliable to test their equality using?
final double di = Double. NaN;
final double d2 Double. NaN;
System.put.println(d1 == d2);

a. True
b. False
c. compile time error
d. Runtime error​

Answer 1

Answer:

false

Explanation:

please mark as brainliest