Question

Given two independent events a, b such that p(a)=0.3, p(b)=0.6. Determine p(neither a nor b)

Answer 1

Answer:

P(neither A nor B) = 0.1

Step-by-step explanation:

We know that the total probability of multiple events adds up to 1 and we also know that there is a probability where neither a nor b happens,

So,

P(A) + P(B) + P(neither A nor B) = 1

0.3 + 0.6 + P(neither A nor B) = 1

0.9 + P(neither A nor B) = 1

P(neither A nor B) = 1 - 0.9

P(neither A nor B) = 0.1

Thank you :) <3 Please correct me if i'm wrong.