Question

Given two independent events, if the probability that exactly one of them occurs is 26/49 and the probability that none of them occurs is 15/49, then the probability of more probable of the two events is:

Answer 1

Given:

The probability that exactly one of them occurs is 26/49

The probability that none of them occurs is 15/49

To find:

The probability of more probable of the two events.

Solution:

1) In probability, the sum of the probability of all the possible events must be equal to 1.

2) P{E} = 1

• P{ exactly one event}+P{exactly two events}+P{none of them} = 1

• 26/49 + P{exactly two events} + 15/49 = 1

• P{exactly two events} + 41/49 = 1

• P{exactly two events} = 1 - 41/49

• P{exactly two events} = (49-41)/49

• P{exactly two events} = 8/49

The probability of more probable of the two events is 8/49.