given two lines 2x-y-1=0 (1) and 3x +y-4=0 (2)and point A(0,4) lying on line (2) find the equation of the line which is symmetric to line (2) with respect to line (1)
let point B which is symmetric to point A with respect to line (1) be (a,b)
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Answer:
−5x+1 = 7y−4 = 1z−0
Step-by-step explanation:
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