Given two triangles, ABC and DEF such that ABC similar to DEF and their areas are 81 cm and 144 cm
respectively. If EF = 16 cm, then find BC.
**URGENT**
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∆ABC ~ ∆ DEF....... given
ABC² = BC²
DEF² EF²
81 = BC
144 16
9 = BC
12 16
12BC = 9× 16
12BC = 144
12BC = 144
BC = 144/12
BC = 12cm
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