given two urns: u contains 4 red and 6 green balls and v contains 5 red and 7 green balls. a ball is selected from u and put unseen in v, where then two ball are selected from v. the probability that the two balls from v are green is
Answers
Given : Two urns: u contains 4 red and 6 green balls and v contains 5 red and 7 green balls.
A ball is selected from u and put unseen in v, where then two ball are selected from v.
To Find : the probability that the two balls from v are green
Solution:
u contains 4 red and 6 green balls
Probability red ball selected = 4/10 = 2/5
Probability green ball selected = 6/10 = 3/5
Red Ball selected then v has 6 Red and 7 green Balls
P (2 G) = ⁷C₂ /¹³C₂ = 7 * 6 / ( 13 * 12) = 7/26
Green Ball selected then v has 5 Red and 8 green Balls
P (2 G) = ⁸C₂ /¹³C₂ = 8 * 7 / ( 13 * 12) = 14/39
probability that the two balls from v are green
= (2/5) ( 7/26) + (3/5)(14/39)
= 7/65 + 14/65
= 21/65
Probability that the two balls from v are green = 21/65
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Answer:
21/65
Step-by-step explanation: