Given U = {10, 11, 12, 13, 14, ... , 20}, A = {10, 12, 14, 16, 18} and B = {10, 11, 12, 13, 14, 15},
1. (AnB)' = A'uB'
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Step-by-step explanation:
solving L.H.S
(AnB)'
AnB={10,12,14}
(AnB)'=U-(AnB)
(AnB)'={11,13,15,16,17,18,19,20}
solving R.H.S
A'nB'
A'=U-A
A'={11,13,15,17,19,20}
B'=U-B
B'={16,17,18,19,20}
A'UB'={11,13,15,16,17,18,19,20}
Hence proved
(AnB)'=A'uB'
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