Question

Given V = 1/3π r² h, find h, when V = 484 c.c. r = 4 cm.​ (algebra)

Answer 1

Answer:

math]f(x)=\displaystyle\frac{x}{\sqrt{x^4+10x^2-96x-71}}[/math]

It has the following elementary antiderivative:

[math]F(x)=-{\frac {1}{8}}\ln \left((x^{6}+15x^{4}-80x^{3}+27x^{2}-528x+781){\sqrt {x^{4}+10x^{2}-96x-71}}-(x^{8}+20x^{6}-128x^{5}+54x^{4}-1408x^{3}+3124x^{2}+10001)\right) [/math]

but the integral of the similar function (where [math]71[/math] is replaced by [math]72[/math])

[math]g(x)=\displaystyle\frac{x}{\sqrt{x^4+10x^2-96x-72}}[/math]

Answer 2

Answer:

$\frac{1}{3} \pi {r}^{2}h = v \\ \frac{1}{3} \times \frac{22}{7} \times {4}^{2} h = 484 \\ h = \frac{484 \times 3 \times 7}{22 \times 16} \\ h = 28.875$

Step-by-step explanation:

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