Question

given v=200sin314 t volt and i=10 sin(314t-38degree) ampere for an ac circuit
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Answer 1

Answer:

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Explanation:

According to the question V=200sin314t and R=10Ω

comaring it with original equation we get ,V

m

=200V

(1} rms voltage , V

rms

=

2

V

m

=0.707×200=141.4V

(2)rms current , I

rms

=

R

V

rms

=

10

141.4

=14.14A

(3)power dissipate ,P=V

rms

I

rms

cosθ

here cosθ is power factor which is equal to 1 for pure resistive circuit since voltage and current are in same phase,

p=141.4×14.14=1999.69≃2000W

Answer 2

Answer:

please make me as brainlist please

Explanation:

According to the question V=200 sin 314t and

R=10

comaring it with original equation we get, V

M

=200V

{1} rms voltage, V

rms

=

2

V

M

=0.707×200=141.4v

(2)rms current,l

rms

=

R

V

rms

=

10

141.4

=14.14A

(3)Power dissipate, P=V

rms

l

rms

cos

here cos is power factor which is equal to l for

pure resistive circuit since voltage and current

are in same phase,

P=141.4×14.14=1999.69 2000w