given vector A= 2i^+3j^ the angle between A^ and y axis is?
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A = 2i + 3j
x = 2
y = 3
If θ is taken as angle between vector and y-axis then,
Tanθ = x / y
= 2 / 3
θ = Tan⁻¹ (2/3)
∴ Angle between vector A and y-axis is Tan⁻¹ (2/3)
x = 2
y = 3
If θ is taken as angle between vector and y-axis then,
Tanθ = x / y
= 2 / 3
θ = Tan⁻¹ (2/3)
∴ Angle between vector A and y-axis is Tan⁻¹ (2/3)
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