Given Vs = 12 V, V2 = 4 V, V3 = 2 V, R1 = 3 Ω, determine the value of the current i passing through the resistor R1
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Answered by
0
Answer:
vs=12
V1+v2+v3=vs
v1+4+2=12
v1=4
I=v/r
4/3a
Answered by
2
Answer:
2A
Explanation:
v1+v2+v3+(-vS)=0
v1+4+2+(-12)=0
v1+(-6)=0
v1=6
I=V/R
I=6V/3 ohms
I = 2A
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