Question

given, x= 1/2-√3 find x^3-2x^2-7x+2​

Answer 1

Answer:

You can see the answer in adjoining pic.

Hope it helps...

Answer 2

Answer:

Hey mate, Good morning ♥️

#Here's ur answer...☆☆☆

Step-by-step explanation:

$x = \frac{1}{2 - \sqrt{3} } \\ = \frac{2 + \sqrt{3} }{(2 - \sqrt{3})(2 + \sqrt{3} )} \\ = \frac{2 + \sqrt{3} }{ {2}^{2} - { (\sqrt{3} )}^{2} } \\ = \frac{2 + \sqrt{3} }{1} \\ = > x - 2 = \sqrt{3} \\ = > (x - 2) {}^{2} = 3 \\ = > {x}^{2} - 4x + 4 = 3 \\ = > {x}^{2} - 4x + 1 = 0$

$= > {x}^{2} - 4x + 1 = 0 \\ = > to \: find... {x}^{3} - 2 {x}^{2} - 7x + 2 \\ = x( {x}^{2} - 4x + 1) + 2 {x}^{2} - 8x + 2 \\ = 0 + 2( {x}^{2} - 4x + 1) \\ = 0(ans)$

Hope this helps you...✌✌✌

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