Question

Given (x+1)î +(y-2)j+(z+2)k is a null vector. 2x+3y+z is equal to​

Answer 1

Answer:

Explanation:

It is given that the following is null vector so

.

x+1 =0

x=-1

y-2=0

y=2

z+2=0

z=-2.

Now put the value in 2x + 3y + z

2 (-1) +3 (2) -2

= -2 +6 -2

= 2