Math, asked by amansharma17, 1 year ago

given x-1/x=root over 15 find.x+1/x,x^2+1/x^2,x^2-1/x^2

Answers

Answered by rakeshmohata
0
Hope u like my process
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 =  >  \bf \: x -  \frac{1}{x}  =  \sqrt{15}  \\  \\  \bf \underline{squaring \:  \: both \:  \: sides} \\  \\  =  >  {(x -  \frac{1}{x} )}^{2}  = 15 \\  \\    =  >  {x}^{2}  +  \frac{1}{ {x}^{2} }  - 2x. \frac{1}{x}  = 15 \\  \\  =  >  \bf {x}^{2}  +  \frac{1}{ {x}^{2} }  = 15  +  2 = \underline{ 17} \\  \\  =  >  {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2 = 17 + 2 \\  \\  =  >  {x}^{2}  +  \frac{1}{ {x}^{2} }  + 2x. \frac{1}{x}  = 19 \\  \\   = >  {(x  +  \frac{1}{ {x} } )}^{2}  = 19 \\  \\  =  > \bf x +  \frac{1}{x}  =  \underline{ \sqrt{19} } \\  \\  \\ now.. \\  \\  \\  =  > \bf  {x}^{2}  -  \frac{1}{ {x}^{2} }  \\  \\  = (x -  \frac{1}{x} )(x +  \frac{1}{x} ) \\  \\  =  \sqrt{15}  \times  \sqrt{19}  \\  \\  =  \bf \underline{ \sqrt{289} }
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