Question

Given, x= 3√5+2√2 and y=3√5-3√5. Find xy, x2 + y2, (x2-y2), x4 +y4, (x2+y2)2.

Answer 1

Answer:

Step-by-step explanation:

GIVEN

x=3√5+2√2 y=3√5-3√

• find xy
• =(3√5+2√2)(3√5-3√5)
• =3√5(3√5-3√5)2√2(3√5-3√5)
• =9*5-9*5*6√10-6√10
• 0*0

• =0

ii)x2+y2

   =(3√5+2√2)2+(3√5-3√5)2

    =6√10+4√4+6√10-6√10

     =6√10+4√4

iii)(x2-y2)

=  (3√5+2√2)2-(3√5-3√5)2

 =6√10+4√4-6√10+6√10

  =6√10+4√4

iv)  x4+y4

   =4(3√5+2√2)+4(3√5-3√5)

   =12√20+8√8+12√20-12√20

    =12√20+8√8

v)  (x2+y2)2

  =2(3√5+2√2)+2(3√5-3√5)2

   =(6√10+4√4+6√10-6√10)2

     =(6√10+4√4)2

     =12√20+8√8

Hope its clear and useful