given x^3=y^4 then prove that (x/y)^4/3+(y/x)^3/4=x^1/3+y^1/4
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Step-by-step explanation:
refer to attachment
now,
put the value of x in equation (1)
y= 132-132-4{6})/3
= (132 - 24)/3
= 108/3
= 36
Attachments:
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