Math, asked by monika1819, 1 year ago

given x+3y =100 when x and y are positive integers .the number of pairs satisfiying the above equation

Answers

Answered by RvChaudharY50
3

Given :- x+3y =100 when x and y are positive integers .the number of pairs satisfying the above equation ?

Solution :-

→ x + 3y = 100

→ x = 100 - 3y

now, given that, x is a positive integer . so,

→ x ≥ 0 .

then,

→ 100 - 3y ≥ 0

→ 3y ≤ 100

→ y ≤ 100/3

→ y ≤ 33.33

therefore,

→ Possible values of y = from 1 to 33 .

hence, we can conclude that, the number of pairs satisfying the equation x + 3y are 33 .

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Answered by meenanitish
0

Answer:

x+3y = 100

x = 100-3y

x = 100-3y ≥ 0 . "(x, y are positive integers)"

transfer '3y' to that side

x = 100 ≥ 3y

= 100 ≥ 3y

transfer '3' to that side

y ≥ 100/3

y ≥ 33.33...

hence, y = 1,2,3,....33

hence there are 33 pairs of equation x+3y = 100

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