given x+3y =100 when x and y are positive integers .the number of pairs satisfiying the above equation
Answers
Given :- x+3y =100 when x and y are positive integers .the number of pairs satisfying the above equation ?
Solution :-
→ x + 3y = 100
→ x = 100 - 3y
now, given that, x is a positive integer . so,
→ x ≥ 0 .
then,
→ 100 - 3y ≥ 0
→ 3y ≤ 100
→ y ≤ 100/3
→ y ≤ 33.33
therefore,
→ Possible values of y = from 1 to 33 .
hence, we can conclude that, the number of pairs satisfying the equation x + 3y are 33 .
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Answer:
x+3y = 100
x = 100-3y
x = 100-3y ≥ 0 . "(x, y are positive integers)"
transfer '3y' to that side
x = 100 ≥ 3y
= 100 ≥ 3y
transfer '3' to that side
y ≥ 100/3
y ≥ 33.33...
hence, y = 1,2,3,....33
hence there are 33 pairs of equation x+3y = 100