Question

Given x=a0+a1t+a2t^2 then acceleration of the particle will be
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Answer 1

Answer:

2x a2

Explanation:

$\frac{ {d}^{2} x}{d {t}^{2} } = f$

$\frac{ {d}^{2} x}{d {t}^{2} } = \frac{d}{dt} ( \frac{dx}{ dt} ) \\ \frac{d}{dt}(a1 + 2.a2t) \\ f = 2.a2</p><p>$