Question

given x and y are positive integers solve x^2 - 4y^2 = 37

Answer 1

x^2 + (2y)^2 = 37
(x + 2y)(x - 2y) = 37
since 37 is a prime number so it has 2 factor that are 1 and itself
Therefore, 
x + 2y = 1, 37
x - 2y = 1, 37
now you can solve accordingly. ANSWER.
thanks