Question

Given x > 0, y = 0, x > y and z = 0. The inequality which is not always
correct is
(a) x + z > y + z
(b) x – z>y - Z
(C) xz > yx
(d) x/z^2 > y/z^2


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Answer 1

Option C

Because 0 Cannot be > 0

Also in option D , the whole comparison becomes undefined because there is 0 in denominator.