Question

Given x/x^2+3x+1=a find the value of x^2/x^4+3x^2+1 is​

Answer 1

Answer:

x/x square =1/x. as according to the question: -->1/x +3x+1= 1+3x square +x . = as 3x square +x+1.

as root is D= b square -4ac .

D= 1-4*(3)*1

D=1-12.

D= -11.(zeroes are not possible) .

x square / x ^4= 1/x square.

ad according to the question: --> 1/x square +3x square +1.= 1+3x^4+x square. ( not a proper equation so, zeroes aren't possible. ).

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