Given x + y = 11 and xy = 20 , Find the value of: (x - y)^2
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Answered by
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Answer:
(x-y)²2
=(x²+y²-2xy)2
={(x+y)²-2xy-2xy}2
={(x+y)²-4xy}2
={(11)²-4×20}2
=(121-80)2
=2×41
=82
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Answered by
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Answer:
(x+y)^2=11^2
x^2+y^2+2ky=121
x^2+y^2+4=121
x^2+y^2=117
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