Question

Given(x+y)=13and xy=22, find the value of x^2+y^2.​

Answer 1

Answer:

125

Step-by-step explanation:

=(x+y)^2-2xy

=13^2-2×22

=169-44

=125

Answer 2

$\tt{{(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy }\\ \boxed{ \bf{{x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy}}$

$\large{ \underline{ \tt{Given : }}}$

$\bf{x + y = 13}$

$\bf{xy = 22}$

$\underline{ \tt{Substituting : }}$

$\tt{ {x}^{2} + {y}^{2} = {(13)}^{2} - 2(22)}$

$\tt{ {x}^{2} + {y}^{2} = 169 - 44}$

$\boxed{ \tt{ {x}^{2} + {y}^{2} = 125}}$

$\\ \\ \red{ \bf{Hope \: \: this \: \: helps \: \: you \: !}}$